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balance_min_flow.py
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balance_min_flow.py
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#!/usr/bin/env python3
# Copyright 2010-2022 Google LLC
# Licensed under the Apache License, Version 2.0 (the "License");
# you may not use this file except in compliance with the License.
# You may obtain a copy of the License at
#
# http://www.apache.org/licenses/LICENSE-2.0
#
# Unless required by applicable law or agreed to in writing, software
# distributed under the License is distributed on an "AS IS" BASIS,
# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
# See the License for the specific language governing permissions and
# limitations under the License.
# [START program]
"""Assignment with teams of workers."""
# [START import]
from ortools.graph.python import min_cost_flow
# [END import]
def main():
"""Solving an Assignment with teams of worker."""
# [START solver]
smcf = min_cost_flow.SimpleMinCostFlow()
# [END solver]
# [START data]
# Define the directed graph for the flow.
team_a = [1, 3, 5]
team_b = [2, 4, 6]
start_nodes = ([0, 0] + [11, 11, 11] + [12, 12, 12] + [
1, 1, 1, 1, 2, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 4, 5, 5, 5, 5, 6, 6, 6, 6
] + [7, 8, 9, 10])
end_nodes = ([11, 12] + team_a + team_b + [
7, 8, 9, 10, 7, 8, 9, 10, 7, 8, 9, 10, 7, 8, 9, 10, 7, 8, 9, 10, 7, 8,
9, 10
] + [13, 13, 13, 13])
capacities = ([2, 2] + [1, 1, 1] + [1, 1, 1] + [
1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1
] + [1, 1, 1, 1])
costs = ([0, 0] + [0, 0, 0] + [0, 0, 0] + [
90, 76, 75, 70, 35, 85, 55, 65, 125, 95, 90, 105, 45, 110, 95, 115, 60,
105, 80, 75, 45, 65, 110, 95
] + [0, 0, 0, 0])
source = 0
sink = 13
tasks = 4
# Define an array of supplies at each node.
supplies = [tasks, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, -tasks]
# [END data]
# [START constraints]
# Add each arc.
for i in range(0, len(start_nodes)):
smcf.add_arc_with_capacity_and_unit_cost(start_nodes[i], end_nodes[i],
capacities[i], costs[i])
# Add node supplies.
for i in range(0, len(supplies)):
smcf.set_node_supply(i, supplies[i])
# [END constraints]
# [START solve]
# Find the minimum cost flow between node 0 and node 10.
status = smcf.solve()
# [END solve]
# [START print_solution]
if status == smcf.OPTIMAL:
print('Total cost = ', smcf.optimal_cost())
print()
for arc in range(smcf.num_arcs()):
# Can ignore arcs leading out of source or intermediate, or into sink.
if (smcf.tail(arc) != source and smcf.tail(arc) != 11 and
smcf.tail(arc) != 12 and smcf.head(arc) != sink):
# Arcs in the solution will have a flow value of 1.
# There start and end nodes give an assignment of worker to task.
if smcf.flow(arc) > 0:
print('Worker %d assigned to task %d. Cost = %d' %
(smcf.tail(arc), smcf.head(arc), smcf.unit_cost(arc)))
else:
print('There was an issue with the min cost flow input.')
print(f'Status: {status}')
# [END print_solution]
if __name__ == '__main__':
main()
# [END program]