@@ -128,6 +128,9 @@ takes for the photon to make one full round trip.
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- The astronomer observes the photon moving at exactly the speed of light, $c$.
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- The astronaut and astronomer disagree on the time it takes for the photon to
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make one full round trip in the light clock.
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+ - The astronaut observes the photon completing one round trip in
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+ $\Delta \tau$.
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+ - The astronomer observes the photon completing one round trip in $\Delta t$.
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**Problem**: Whose round-trip duration measurement is correct?
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@@ -139,12 +142,12 @@ In the astronaut's inertial frame:
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- The light clock is at rest so the photon travels $2D$ in the time it takes to
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complete one round trip.
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- The time it takes for the photon to make one full round trip is
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- $\Delta t = \frac{2D}{c}$.
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+ $\Delta \tau = \frac{2D}{c}$.
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In the astronomer's inertial frame:
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- The photon moves at speed $c$.
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- - The light clock is moving so the photon travels a longer distance in the time
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- it takes to make one full round trip.
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+ - The light clock is moving relative to the astronomer so the photon travels a
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+ longer distance in the time it takes to make one full round trip in the clock .
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- The photon travels sideways a distance $v \Delta t$ in addition to the
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distance $2D$ it travels up and down between the mirrors.
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- The total distance the photon travels can be found by pythagorean theorem.
@@ -153,8 +156,8 @@ In the astronomer's inertial frame:
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$$
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s = \sqrt{(2D)^2 + (v \Delta t)^2}
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$$
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- - The time it takes for the photon to make one full round trip is
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- $\Delta t = \frac{2 \sqrt{D^2 + (v \Delta t)^2}}{c}$.
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+
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+
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```
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We see here that both of Einstein's postulates are satisfied, and we have not
@@ -169,3 +172,12 @@ counterintuitive as it may be,
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```
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### Exploring time dilation
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+
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+ In the astronomer's reference frame, the photon moves across more space over the
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+ course of one "tick" of the clock. The only way the speed of the photon, $c$,
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+ can be the same in all reference frames and yet travel across more distance in
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+ one reference frame than in another is if the elapsed time experienced by a
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+ moving object, $\Delta \tau$, "dilates" compared to the elapsed time
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+ experienced by an observer at rest in the reference frame, $\Delta t$.
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+
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+ ![ time dilation] ( ./assets/TimeDilationDemo.gif )
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