title | layout |
---|---|
Right Triangle Trigonometry |
page |
45°( π 4 ),
and 60°( π 3 ).
- Use cofunctions of complementary angles.
- Use the definitions of trigonometric functions of any angle.
- Use right triangle trigonometry to solve applied problems.
We have previously defined the sine and cosine of an angle in terms of the coordinates of a point on the unit circle intersected by the terminal side of the angle:
In this section, we will see another way to define trigonometric functions using properties of right triangles{: data-type="term" .no-emphasis}.
In earlier sections, we used a unit circle to define the trigonometric functions{: data-type="term" .no-emphasis}. In this section, we will extend those definitions so that we can apply them to right triangles. The value of the sine or cosine function of t
is its value at t
radians. First, we need to create our right triangle. [link] shows a point on a unit circle{: data-type="term" .no-emphasis} of radius 1. If we drop a vertical line segment from the point (x,y)
to the x-axis, we have a right triangle whose vertical side has length y
and whose horizontal side has length x.
We can use this right triangle to redefine sine, cosine, and the other trigonometric functions as ratios of the sides of a right triangle.
We know
Likewise, we know
These ratios still apply to the sides of a right triangle when no unit circle is involved and when the triangle is not in standard position and is not being graphed using (x,y)
coordinates. To be able to use these ratios freely, we will give the sides more general names: Instead of x,
we will call the side between the given angle and the right angle the adjacent side{: data-type="term"} to angle t.
(Adjacent means “next to.”) Instead of y,
we will call the side most distant from the given angle the opposite side{: data-type="term"} from angle t.
And instead of 1,
we will call the side of a right triangle opposite the right angle the hypotenuse{: data-type="term"}. These sides are labeled in [link].
Given a right triangle with an acute angle of t,
A common mnemonic for remembering these relationships is SohCahToa, formed from the first letters of “Sine is opposite over hypotenuse, Cosine is adjacent over hypotenuse, Tangent is opposite over adjacent.”
- Find the sine as the ratio of the opposite side to the hypotenuse.
- Find the cosine as the ratio of the adjacent side to the hypotenuse.
- Find the tangent as the ratio of the opposite side to the adjacent side. {: type="1"}
When working with right triangles, the same rules apply regardless of the orientation of the triangle. In fact, we can evaluate the six trigonometric functions of either of the two acute angles in the triangle in [link]. The side opposite one acute angle is the side adjacent to the other acute angle, and vice versa.
We will be asked to find all six trigonometric functions for a given angle in a triangle. Our strategy is to find the sine, cosine, and tangent of the angles first. Then, we can find the other trigonometric functions easily because we know that the reciprocal of sine is cosecant, the reciprocal of cosine is secant, and the reciprocal of tangent is cotangent.
- If needed, draw the right triangle and label the angle provided.
- Identify the angle, the adjacent side, the side opposite the angle, and the hypotenuse of the right triangle.
- Find the required function:
- sine as the ratio of the opposite side to the hypotenuse
- cosine as the ratio of the adjacent side to the hypotenuse
- tangent as the ratio of the opposite side to the adjacent side
- secant as the ratio of the hypotenuse to the adjacent side
- cosecant as the ratio of the hypotenuse to the opposite side
- cotangent as the ratio of the adjacent side to the opposite side {: type="1"}
cos α,
tan α,
sec α,
csc α,
and cot α.
We have already discussed the trigonometric functions as they relate to the special angles{: data-type="term" .no-emphasis} on the unit circle. Now, we can use those relationships to evaluate triangles that contain those special angles. We do this because when we evaluate the special angles in trigonometric functions, they have relatively friendly values, values that contain either no or just one square root in the ratio. Therefore, these are the angles often used in math and science problems. We will use multiples of 30°,
60°,
and 45°,
however, remember that when dealing with right triangles, we are limited to angles between 0° and 90°.
Suppose we have a 30°,60°,90°
triangle, which can also be described as a π 6 , π 3 , π 2
triangle. The sides have lengths in the relation s, 3 s,2s.
The sides of a 45°,45°,90°
triangle, which can also be described as a π 4 , π 4 , π 2
triangle, have lengths in the relation s,s, 2 s.
These relations are shown in [link].
We can then use the ratios of the side lengths to evaluate trigonometric functions of special angles.
- Use the side lengths shown in [link] for the special angle you wish to evaluate.
- Use the ratio of side lengths appropriate to the function you wish to evaluate. {: type="1"}
using side lengths.
using side lengths.
{: data-type="newline"}
sec( π 4 )= 2 ,csc( π 4 )= 2 ,cot( π 4 )=1
If we look more closely at the relationship between the sine and cosine of the special angles relative to the unit circle, we will notice a pattern. In a right triangle with angles of π 6
and π 3 ,
we see that the sine of π 3 ,
namely 3 2 ,
is also the cosine of π 6 ,
while the sine of π 6 ,
namely 1 2 ,
is also the cosine of π 3 .
See [link]
This result should not be surprising because, as we see from [link], the side opposite the angle of π 3
is also the side adjacent to π 6 ,
so sin( π 3 )
and cos( π 6 )
are exactly the same ratio of the same two sides, 3 s
and 2s.
Similarly, cos( π 3 )
and sin( π 6 )
are also the same ratio using the same two sides, s
and 2s.
The interrelationship between the sines and cosines of π 6
and π 3
also holds for the two acute angles in any right triangle, since in every case, the ratio of the same two sides would constitute the sine of one angle and the cosine of the other. Since the three angles of a triangle add to π,
and the right angle is π 2 ,
the remaining two angles must also add up to π 2 .
That means that a right triangle can be formed with any two angles that add to π 2
—in other words, any two complementary angles. So we may state a cofunction identity: If any two angles are complementary, the sine of one is the cosine of the other, and vice versa. This identity is illustrated in [link].
Using this identity, we can state without calculating, for instance, that the sine of π 12
equals the cosine of 5π 12 ,
and that the sine of 5π 12
equals the cosine of π 12 .
We can also state that if, for a certain angle t,
cos t= 5 13 ,
then sin( π 2 −t )= 5 13
as well.
| cos t=sin( π 2 −t )
| sin t=cos( π 2 −t )
| | tan t=cot( π 2 −t )
| cot t=tan( π 2 −t )
| | sec t=csc( π 2 −t )
| csc t=sec( π 2 −t )
| {: #Table_05_04_01 summary=".."}
- To find the sine of the complementary angle, find the cosine of the original angle.
- To find the cosine of the complementary angle, find the sine of the original angle. {: type="1"}
find ( cos π 2 −t ).
find sec( π 3 ).
In previous examples, we evaluated the sine and cosine in triangles where we knew all three sides. But the real power of right-triangle trigonometry emerges when we look at triangles in which we know an angle but do not know all the sides.
- For each side, select the trigonometric function that has the unknown side as either the numerator or the denominator. The known side will in turn be the denominator or the numerator.
- Write an equation setting the function value of the known angle equal to the ratio of the corresponding sides.
- Using the value of the trigonometric function and the known side length, solve for the missing side length. {: type="1"}
and a hypotenuse of 20. Find the unknown sides and angle of the triangle.
opposite=10 3
; missing angle is π 6
Right-triangle trigonometry has many practical applications. For example, the ability to compute the lengths of sides of a triangle makes it possible to find the height of a tall object without climbing to the top or having to extend a tape measure along its height. We do so by measuring a distance from the base of the object to a point on the ground some distance away, where we can look up to the top of the tall object at an angle. The angle of elevation{: data-type="term"} of an object above an observer relative to the observer is the angle between the horizontal and the line from the object to the observer's eye. The right triangle this position creates has sides that represent the unknown height, the measured distance from the base, and the angled line of sight from the ground to the top of the object. Knowing the measured distance to the base of the object and the angle of the line of sight, we can use trigonometric functions to calculate the unknown height. Similarly, we can form a triangle from the top of a tall object by looking downward. The angle of depression{: data-type="term"} of an object below an observer relative to the observer is the angle between the horizontal and the line from the object to the observer's eye. See [link].
- Make a sketch of the problem situation to keep track of known and unknown information.
- Lay out a measured distance from the base of the object to a point where the top of the object is clearly visible.
- At the other end of the measured distance, look up to the top of the object. Measure the angle the line of sight makes with the horizontal.
- Write an equation relating the unknown height, the measured distance, and the tangent of the angle of the line of sight.
- Solve the equation for the unknown height. {: type="1"}
between a line of sight to the top of the tree and the ground, as shown in [link]. Find the height of the tree.
and the adjacent side is 30 ft long. The opposite side is the unknown height.
The trigonometric function relating the side opposite to an angle and the side adjacent to the angle is the tangent. So we will state our information in terms of the tangent of 57°,
letting h
be the unknown height.
with the ground? Round to the nearest foot.
Visit this website for additional practice questions from Learningpod.
| Cofunction Identities | cos t=sin( π 2 −t ) sin t=cos( π 2 −t ) tan t=cot( π 2 −t ) cot t=tan( π 2 −t ) sec t=csc( π 2 −t ) csc t=sec( π 2 −t )
| {: #eip-id1165137409421 summary=".."}
- We can define trigonometric functions as ratios of the side lengths of a right triangle. See [link].
- The same side lengths can be used to evaluate the trigonometric functions of either acute angle in a right triangle. See [link].
- We can evaluate the trigonometric functions of special angles, knowing the side lengths of the triangles in which they occur. See [link].
- Any two complementary angles could be the two acute angles of a right triangle.
- If two angles are complementary, the cofunction identities state that the sine of one equals the cosine of the other and vice versa. See [link].
- We can use trigonometric functions of an angle to find unknown side lengths.
- Select the trigonometric function representing the ratio of the unknown side to the known side. See [link].
- Right-triangle trigonometry permits the measurement of inaccessible heights and distances.
- The unknown height or distance can be found by creating a right triangle in which the unknown height or distance is one of the sides, and another side and angle are known. See [link].
For the following exercises, use cofunctions of complementary angles.
For the following exercises, find the lengths of the missing sides if side a
is opposite angle A,
side b
is opposite angle B,
and side c
is the hypotenuse.
For the following exercises, use [link] to evaluate each trigonometric function of angle A.
For the following exercises, use [link] to evaluate each trigonometric function of angle A.
For the following exercises, solve for the unknown sides of the given triangle.
For the following exercises, use a calculator to find the length of each side to four decimal places.
and that the angle of depression to the bottom of the tower is 23°.
How tall is the tower?
and that the angle of depression to the bottom of the tower is 31°.
How tall is the tower?
and that the angle of depression to the bottom of the tower is 2°.
How far is the person from the monument?
and that the angle of depression to the bottom of the monument is 3°.
How far is the person from the monument?
From the same location, the angle of elevation to the top of the antenna is measured to be 43°.
Find the height of the antenna.
From the same location, the angle of elevation to the top of the lightning rod is measured to be 38°.
Find the height of the lightning rod.
How high does the ladder reach up the side of the building?
How high does the ladder reach up the side of the building?
how far from the base of the tree am I?
Angles{: .target-chapter}
For the following exercises, convert the angle measures to degrees.
For the following exercises, convert the angle measures to radians.
radians.
For the following exercises, find the angle between 0° and 360° that is coterminal with the given angle.
For the following exercises, find the angle between 0 and 2π
in radians that is coterminal with the given angle.
For the following exercises, draw the angle provided in standard position on the Cartesian plane.
Unit Circle: Sine and Cosine Functions{: .target-chapter}
The Other Trigonometric Functions{: .target-chapter}
For the following exercises, find the exact value of the given expression.
For the following exercises, use reference angles to evaluate the given expression.
, what is the sec(−t)?
what is the tan(−t)?
find tan(t−π).
find sin(t+2π).
or − 2 2
Right Triangle Trigonometry{: .target-chapter}
For the following exercises, use side lengths to evaluate.
For the following exercises, use the given information to find the lengths of the other two sides of the right triangle.
For the following exercises, use [link] to evaluate each trigonometric function.
For the following exercises, solve for the unknown sides of the given triangle.
How high does the ladder reach up the side of the building?
radians to degrees.
to radians.
radians.
and 360°
that is coterminal with 375°.
in radians that is coterminal with − 4π 7 .
in standard position on the Cartesian plane.
in standard position on the Cartesian plane.
radians per second
what is the csc(−t)?
find cos(t−2π).
adjacent side : in a right triangle, the side between a given angle and the right angle ^
angle of depression : the angle between the horizontal and the line from the object to the observer’s eye, assuming the object is positioned lower than the observer ^
angle of elevation : the angle between the horizontal and the line from the object to the observer’s eye, assuming the object is positioned higher than the observer ^
opposite side : in a right triangle, the side most distant from a given angle ^
hypotenuse : the side of a right triangle opposite the right angle