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sum-of-digits-of-string-after-convert.rs
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// 1945. Sum of Digits of String After Convert
// 🟢 Easy
//
// https://leetcode.com/problems/sum-of-digits-of-string-after-convert/
//
// Tags: String - Simulation
struct Solution;
impl Solution {
/// Convert the input string to an integer, then sum its digits k time.
///
/// Time complexity: O(n) - We iterate over each character to get its integer value.
/// Space complexity: O(1) - We use usize extra memory.
///
/// Runtime 1 ms Beats 68%
/// Memory 2.14 MB Beats 36%
pub fn get_lucky(s: String, k: i32) -> i32 {
fn sum_digits(mut num: usize) -> usize {
let mut res = 0;
while num > 0 {
res += num % 10;
num /= 10;
}
res
}
let mut num = s.bytes().map(|b| sum_digits((b - b'a' + 1) as usize)).sum();
for _ in 0..k - 1 {
num = sum_digits(num);
if num < 10 {
return num as i32;
}
}
num as i32
}
}
// Tests.
fn main() {
let tests = [
(String::from("iiii"), 1, 36),
(String::from("leetcode"), 2, 6),
(String::from("zbax"), 2, 8),
];
println!("\n\x1b[92m» Running {} tests...\x1b[0m", tests.len());
let mut success = 0;
for (i, t) in tests.iter().enumerate() {
let res = Solution::get_lucky(t.0.clone(), t.1);
if res == t.2 {
success += 1;
println!("\x1b[92m✔\x1b[95m Test {} passed!\x1b[0m", i);
} else {
println!(
"\x1b[31mx\x1b[95m Test {} failed expected: {:?} but got {}!!\x1b[0m",
i, t.2, res
);
}
}
println!();
if success == tests.len() {
println!("\x1b[30;42m✔ All tests passed!\x1b[0m")
} else if success == 0 {
println!("\x1b[31mx \x1b[41;37mAll tests failed!\x1b[0m")
} else {
println!(
"\x1b[31mx\x1b[95m {} tests failed!\x1b[0m",
tests.len() - success
)
}
}