forked from saumya81/DSA
-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy pathEqual sum partitioning.cpp
56 lines (44 loc) · 1.26 KB
/
Equal sum partitioning.cpp
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
// Given a non-empty array nums containing only positive integers, find if the array can be partitioned into two subsets such that the sum of elements in both subsets is equal.
// Example 1:
// Input: nums = [1,5,11,5]
// Output: true
// Explanation: The array can be partitioned as [1, 5, 5] and [11].
class Solution {
public:
bool subsetSum(vector<int> a,int s)
{
int n=a.size();
bool dp[n+1][s+1];
for(int i=0;i<n+1;i++){
for(int j=0;j<s+1;j++)
{
if(i==0)
dp[i][j]=false;
if(j==0)
dp[i][j]=true;
}}
for(int i=1;i<n+1;i++)
{
for(int j=1;j<s+1;j++)
{
if(a[i-1]<=j)
{
dp[i][j]=dp[i-1][j] | dp[i-1][j-a[i-1]];
}
else
dp[i][j]=dp[i-1][j];
}
}
return dp[n][s];
}
bool canPartition(vector<int>& a) {
int sum=0;
for(int i=0;i<a.size();i++)
sum=sum+a[i];
//it cannot be possible if sum of element is odd
if(sum%2!=0)
return false;
else
return subsetSum(a,sum/2);
}
};