-
Notifications
You must be signed in to change notification settings - Fork 1
/
design_add_and_search_words.py
56 lines (37 loc) · 1.24 KB
/
design_add_and_search_words.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
'''
Question: https://leetcode.com/problems/design-add-and-search-words-data-structure/
'''
class TrieNode:
def __init__(self):
self.children = {} # {a: TrieNode()}
self.endOfWord = False
class WordDictionary:
def __init__(self):
self.root = TrieNode()
def addWord(self, word: str) -> None:
cur = self.root
for c in word:
if c not in cur.children:
cur.children[c] = TrieNode()
cur = cur.children[c]
cur.endOfWord = True
def search(self, word: str) -> bool:
return self.dfs(0, self.root, word)
def dfs(self, j, root, word) -> bool:
cur = root
for i in range(j, len(word)):
c = word[i]
if c == ".":
for child in cur.children.values():
if self.dfs(i + 1, child, word):
return True
return False
else:
if c not in cur.children:
return False
cur = cur.children[c]
return cur.endOfWord
# Your WordDictionary object will be instantiated and called as such:
# obj = WordDictionary()
# obj.addWord(word)
# param_2 = obj.search(word)