diff --git a/01-NthHighestSalary.py b/01-NthHighestSalary.py
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+++ b/01-NthHighestSalary.py
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+# Problem 1 - Nth Highest Salary (https://leetcode.com/problems/nth-highest-salary/solution/)
+import pandas as pd
+
+def nth_highest_salary(employee: pd.DataFrame, N: int) -> pd.DataFrame:
+    # Dropping duplicate salaries from table
+    df = employee[['salary']].drop_duplicates()
+
+    # Returning null if N is greater than number of salaries in table or if N is less than or equal to 0
+    if N > len(df) or N <= 0:
+        return pd.DataFrame({f'getNthHighestSalary({N})' : [None]})
+    
+    # Ordering salaries in descending order and returning the N top ones. The tail function filters out the distinct Nth highest salary
+    return df.sort_values('salary', ascending = False).head(N).tail(1)[['salary']].rename(columns = {'salary':f'getNthHighestSalary({N})'})
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diff --git a/02-SecondHighestSalary.py b/02-SecondHighestSalary.py
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+++ b/02-SecondHighestSalary.py
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+# Problem 2 - Second Highest Salary ( https://leetcode.com/problems/second-highest-salary/ )
+import pandas as pd
+
+def second_highest_salary(employee: pd.DataFrame) -> pd.DataFrame:
+    # Dropping duplicate salary values
+    df = employee[['salary']].drop_duplicates()
+    # Returning None if number of salaries is less than 2
+    if len(df) < 2:
+        return pd.DataFrame({'SecondHighestSalary' : [None]})
+    # Returning 2nd Highest Salary
+    return df.sort_values('salary', ascending = False).head(2).tail(1)[['salary']].rename(columns = {'salary':'SecondHighestSalary'})