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assertion.py
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67 lines (58 loc) · 2.27 KB
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# By Websten from forums
#
# Given your birthday and the current date, calculate your age in days.
# Compensate for leap days.
# Assume that the birthday and current date are correct dates (and no time travel).
# Simply put, if you were born 1 Jan 2012 and todays date is 2 Jan 2012
# you are 1 day old.
#
# Hint
# A whole year is 365 days, 366 if a leap year.
def nextDay(year, month, day):
"""Simple version: assume every month has 30 days"""
if day < 30:
return year, month, day + 1
else:
if month == 12:
return year + 1, 1, 1
else:
return year, month + 1, 1
def dateIsAfter(year1, month1, day1, year2, month2, day2):
"""Returns True if year1-month1-day1 is after year2-month2-day2. Otherwise, returns False."""
if year1 > year2:
return True
if year1 == year2:
if month1 > month2:
return True
if month1 == month2:
return day1 > day2
return False
def daysBetweenDates(year1, month1, day1, year2, month2, day2):
"""Returns the number of days between year1/month1/day1
and year2/month2/day2. Assumes inputs are valid dates
in Gregorian calendar."""
# program defensively! Add an assertion if the input is not valid!
assert ((year1<year2)or((year1==year2)and(month1<=month2)and(day1<=day2)))
days = 0
while dateIsAfter(year2, month2, day2, year1, month1, day1):
days += 1
(year1, month1, day1) = nextDay(year1, month1, day1)
return days
def test():
test_cases = [((2012,9,30,2012,10,30),30),
((2012,1,1,2013,1,1),360),
((2012,9,1,2012,9,4),3),
((2013,1,1,1999,12,31), "AssertionError")]
for (args, answer) in test_cases:
try:
result = daysBetweenDates(*args)
if result != answer:
print ("Test with data:", args, "failed")
else:
print ("Test case passed!")
except AssertionError:
if answer == "AssertionError":
print ("Nice job! Test case {0} correctly raises AssertionError!\n".format(args))
else:
print ("Check your work! Test case {0} should not raise AssertionError!\n".format(args))
test()