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019.remove-nth-node-from-end-of-list

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给你一个链表,删除链表的倒数第 n 个结点,并且返回链表的头结点。

 

示例 1:

输入:head = [1,2,3,4,5], n = 2
输出:[1,2,3,5]

示例 2:

输入:head = [1], n = 1
输出:[]

示例 3:

输入:head = [1,2], n = 1
输出:[1]

 

提示:

  • 链表中结点的数目为 sz
  • 1 <= sz <= 30
  • 0 <= Node.val <= 100
  • 1 <= n <= sz

 

进阶:你能尝试使用一趟扫描实现吗?

Hints

  1. Maintain two pointers and update one with a delay of n steps.