You are playing the Bulls and Cows game with your friend.
You write down a secret number and ask your friend to guess what the number is. When your friend makes a guess, you provide a hint with the following info:
- The number of "bulls", which are digits in the guess that are in the correct position.
- The number of "cows", which are digits in the guess that are in your secret number but are located in the wrong position. Specifically, the non-bull digits in the guess that could be rearranged such that they become bulls.
Given the secret number secret
and your friend's guess guess
, return the hint for your friend's guess.
The hint should be formatted as "xAyB"
, where x
is the number of bulls and y
is the number of cows. Note that both secret
and guess
may contain duplicate digits.
Example 1:
Input: secret = "1807", guess = "7810" Output: "1A3B" Explanation: Bulls are connected with a '|' and cows are underlined: "1807" | "7810"
Example 2:
Input: secret = "1123", guess = "0111" Output: "1A1B" Explanation: Bulls are connected with a '|' and cows are underlined: "1123" "1123" | or | "0111" "0111" Note that only one of the two unmatched 1s is counted as a cow since the non-bull digits can only be rearranged to allow one 1 to be a bull.
Constraints:
1 <= secret.length, guess.length <= 1000
secret.length == guess.length
secret
andguess
consist of digits only.
class Solution:
def getHint(self, secret: str, guess: str) -> str:
x = y = 0
cnt1 = [0] * 10
cnt2 = [0] * 10
for i in range(len(secret)):
if secret[i] == guess[i]:
x += 1
else:
cnt1[int(secret[i])] += 1
cnt2[int(guess[i])] += 1
for i in range(10):
y += min(cnt1[i], cnt2[i])
return f'{x}A{y}B'
class Solution {
public String getHint(String secret, String guess) {
int x = 0, y = 0;
int[] cnt1 = new int[10];
int[] cnt2 = new int[10];
for (int i = 0; i < secret.length(); ++i) {
int a = secret.charAt(i) - '0', b = guess.charAt(i) - '0';
if (a == b) {
++x;
} else {
++cnt1[a];
++cnt2[b];
}
}
for (int i = 0; i < 10; ++i) {
y += Math.min(cnt1[i], cnt2[i]);
}
return String.format("%dA%dB", x, y);
}
}
class Solution {
public:
string getHint(string secret, string guess) {
int x = 0, y = 0;
vector<int> cnt1(10);
vector<int> cnt2(10);
for (int i = 0; i < secret.size(); ++i)
{
int a = secret[i] - '0', b = guess[i] - '0';
if (a == b) ++x;
else
{
++cnt1[a];
++cnt2[b];
}
}
for (int i = 0; i < 10; ++i) y += min(cnt1[i], cnt2[i]);
return to_string(x) + "A" + to_string(y) + "B";
}
};
func getHint(secret string, guess string) string {
x, y := 0, 0
cnt1 := make([]int, 10)
cnt2 := make([]int, 10)
for i := 0; i < len(secret); i++ {
a, b := secret[i]-'0', guess[i]-'0'
if a == b {
x++
} else {
cnt1[a]++
cnt2[b]++
}
}
for i := 0; i < 10; i++ {
y += min(cnt1[i], cnt2[i])
}
return fmt.Sprintf("%dA%dB", x, y)
}
func min(a, b int) int {
if a < b {
return a
}
return b
}