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804. Unique Morse Code Words

中文文档

Description

International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows:

  • 'a' maps to ".-",
  • 'b' maps to "-...",
  • 'c' maps to "-.-.", and so on.

For convenience, the full table for the 26 letters of the English alphabet is given below:

[".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."]

Given an array of strings words where each word can be written as a concatenation of the Morse code of each letter.

  • For example, "cab" can be written as "-.-..--...", which is the concatenation of "-.-.", ".-", and "-...". We will call such a concatenation the transformation of a word.

Return the number of different transformations among all words we have.

 

Example 1:

Input: words = ["gin","zen","gig","msg"]
Output: 2
Explanation: The transformation of each word is:
"gin" -> "--...-."
"zen" -> "--...-."
"gig" -> "--...--."
"msg" -> "--...--."
There are 2 different transformations: "--...-." and "--...--.".

Example 2:

Input: words = ["a"]
Output: 1

 

Constraints:

  • 1 <= words.length <= 100
  • 1 <= words[i].length <= 12
  • words[i] consists of lowercase English letters.

Solutions

Python3

class Solution:
    def uniqueMorseRepresentations(self, words: List[str]) -> int:
        codes = [".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."]
        s = set()
        for word in words:
            t = []
            for c in word:
                t.append(codes[ord(c) - ord('a')])
            s.add(''.join(t))
        return len(s)

Java

class Solution {
    public int uniqueMorseRepresentations(String[] words) {
        String[] codes = new String[]{".-", "-...", "-.-.", "-..", ".", "..-.", "--.", "....", "..", ".---", "-.-", ".-..", "--", "-.", "---", ".--.", "--.-", ".-.", "...", "-", "..-", "...-", ".--", "-..-", "-.--", "--.."};
        Set<String> s = new HashSet<>();
        for (String word : words) {
            StringBuilder t = new StringBuilder();
            for (char c : word.toCharArray()) {
                t.append(codes[c - 'a']);
            }
            s.add(t.toString());
        }
        return s.size();
    }
}

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