You are given a string sentence
that consist of words separated by spaces. Each word consists of lowercase and uppercase letters only.
We would like to convert the sentence to "Goat Latin" (a made-up language similar to Pig Latin.) The rules of Goat Latin are as follows:
- If a word begins with a vowel (
'a'
,'e'
,'i'
,'o'
, or'u'
), append"ma"
to the end of the word.- For example, the word
"apple"
becomes"applema"
.
- For example, the word
- If a word begins with a consonant (i.e., not a vowel), remove the first letter and append it to the end, then add
"ma"
.- For example, the word
"goat"
becomes"oatgma"
.
- For example, the word
- Add one letter
'a'
to the end of each word per its word index in the sentence, starting with1
.- For example, the first word gets
"a"
added to the end, the second word gets"aa"
added to the end, and so on.
- For example, the first word gets
Return the final sentence representing the conversion from sentence to Goat Latin.
Example 1:
Input: sentence = "I speak Goat Latin" Output: "Imaa peaksmaaa oatGmaaaa atinLmaaaaa"
Example 2:
Input: sentence = "The quick brown fox jumped over the lazy dog" Output: "heTmaa uickqmaaa rownbmaaaa oxfmaaaaa umpedjmaaaaaa overmaaaaaaa hetmaaaaaaaa azylmaaaaaaaaa ogdmaaaaaaaaaa"
Constraints:
1 <= sentence.length <= 150
sentence
consists of English letters and spaces.sentence
has no leading or trailing spaces.- All the words in
sentence
are separated by a single space.
class Solution:
def toGoatLatin(self, sentence: str) -> str:
ans = []
for i, word in enumerate(sentence.split()):
if word.lower()[0] not in ['a', 'e', 'i', 'o', 'u']:
word = word[1:] + word[0]
word += 'ma'
word += 'a' * (i + 1)
ans.append(word)
return ' '.join(ans)
class Solution {
public String toGoatLatin(String sentence) {
List<String> ans = new ArrayList<>();
Set<Character> vowels = new HashSet<>(Arrays.asList('a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U'));
int i = 1;
for (String word : sentence.split(" ")) {
StringBuilder t = new StringBuilder();
if (!vowels.contains(word.charAt(0))) {
t.append(word.substring(1));
t.append(word.charAt(0));
} else {
t.append(word);
}
t.append("ma");
for (int j = 0; j < i; ++j) {
t.append("a");
}
++i;
ans.add(t.toString());
}
return String.join(" ", ans);
}
}