README_EN.md

1502. Can Make Arithmetic Progression From Sequence

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Description

A sequence of numbers is called an arithmetic progression if the difference between any two consecutive elements is the same.

Given an array of numbers arr, return true if the array can be rearranged to form an arithmetic progression. Otherwise, return false.

 

Example 1:

Input: arr = [3,5,1]
Output: true
Explanation: We can reorder the elements as [1,3,5] or [5,3,1] with differences 2 and -2 respectively, between each consecutive elements.

Example 2:

Input: arr = [1,2,4]
Output: false
Explanation: There is no way to reorder the elements to obtain an arithmetic progression.

 

Constraints:

• 2 <= arr.length <= 1000
• -106 <= arr[i] <= 106

Solutions

Python3

class Solution:
    def canMakeArithmeticProgression(self, arr: List[int]) -> bool:
        arr.sort()
        for i in range(1, len(arr) - 1):
            if (arr[i] << 1) != arr[i - 1] + arr[i + 1]:
                return False
        return True

Java

class Solution {
    public boolean canMakeArithmeticProgression(int[] arr) {
        Arrays.sort(arr);
        for (int i = 1; i < arr.length - 1; ++i) {
            if ((arr[i] << 1) != arr[i - 1] + arr[i + 1]) {
                return false;
            }
        }
        return true;
    }
}

JavaScript

/**
 * @param {number[]} arr
 * @return {boolean}
 */
var canMakeArithmeticProgression = function (arr) {
    arr.sort((a, b) => a - b);
    for (let i = 1; i < arr.length - 1; i++) {
        if (arr[i] << 1 != arr[i - 1] + arr[i + 1]) return false;
    }
    return true;
};

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