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finished #1

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152 changes: 152 additions & 0 deletions solution.js
Original file line number Diff line number Diff line change
@@ -1,5 +1,157 @@
const { nums, words } = require("./data/data.js");


class Node {
constructor(data) {
this.data = data;
this.next = null;
}
};


class LinkedList {
constructor(head = null) {
this.head = head
};

size() {

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Can you think of a way to have this function run in O(1) instead of O(n)?

let count = 0;
let currentNode = this.head;
while(currentNode) {
count++;
currentNode = currentNode.next;
}
return count;
};

search(value) {
let currentNode = this.head;
while(currentNode) {
if (currentNode.data === value) {
return currentNode;
};
currentNode = currentNode.next;
};
};

clear() {
this.head = null;
}

getFirst() {
return this.head;
}

getLast() {
let currentNode = this.head
while(currentNode.next != null){
currentNode = currentNode.next;
}
return currentNode;
}

insert(value) {
let newNode = new Node(value);
if(!this.head){
this.head = newNode;
} else {
newNode.next = this.head;
this.head = newNode;
}
}


delete(position) {
if (position <= 0 || position > this.size()) {
return;
}
if (position === 1) {
this.head = this.head.next;
return;
}
let currentNode = this.head;
let count = 1;
while (count < position - 1) {
currentNode = currentNode.next;
count++;
}
currentNode.next = currentNode.next.next;
};

isEmpty() {
let count = 0;

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There's a way to write this in one line and O(n) run time

let currentNode = this.head;
while(currentNode) {
count++;
currentNode = currentNode.next;
}
if(count === 0){
return true
} else {
return false
}
}

getKth(position) {
let count = 0;
let currentNode = this.head;
while(currentNode != null) {
count ++
if(count === position){
return currentNode
}
currentNode = currentNode.next
}
}

getKthToLast(kth) {
let slow = this.head;
let fast = this.head.next;
for (let i = 0; i < kth; i++) {
fast = fast.next
}
while (fast != null) {
slow = slow.next;
fast = fast.next;
}
return slow;
}

toArray() {
let currentNode = this.head
let arr = []
while(currentNode) {
arr.push(currentNode.data)
currentNode = currentNode.next
}
return arr
}

containsDuplicates() {
let visited = new Set();

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Using a set you could compare the length of the set to the size of the linked list for shorter, cleaner code

let currentNode = this.head;
while (currentNode) {
if (visited.has(currentNode.data)) {
return true;
}
visited.add(currentNode.data);
currentNode = currentNode.next;
}
return false;
}
};

let numsHead = new Node(nums[0])
let list = new LinkedList(numsHead);
for (let i = 1; i < nums.length; i++) {
let currentNode = new Node(nums[i]);
numsHead.next = currentNode;
numsHead = currentNode;
}

console.log(list.getKthToLast(8))


module.exports = {
Node,
LinkedList,
Expand Down