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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,26 @@ | ||
| from collections import deque | ||
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| def solution(bridge_length, weight, truck_weights): | ||
| time = 0 | ||
| onBridge = deque() # νμ¬ λ€λ¦¬ μμ μλ νΈλ | ||
| truckNum = 0 # νμ¬ λ€λ¦¬ μμ μλ νΈλ μ | ||
| sum = 0 # νμ¬ λ€λ¦¬ μμ μλ νΈλ 무κ²μ ν© | ||
| truck_weights = deque(truck_weights) | ||
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| while truck_weights or onBridge: | ||
| time += 1 | ||
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| # νΈλμ΄ λ€λ¦¬λ₯Ό μ§λκ°λ κ²½μ° μ²λ¦¬ | ||
| if onBridge and time - onBridge[0][1] >= bridge_length: | ||
| sum -= onBridge.popleft()[0] | ||
| truckNum -= 1 | ||
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| # λ€μ νΈλμ΄ λ€λ¦¬μ μ¬λΌκ° μ μλ κ²½μ° μ²λ¦¬ | ||
| # νΈλμ΄ μκ³ ν©μ΄ weightμ λμ§ μμΌλ©°, μκ° bridge_lengthλ₯Ό λκΈ°μ§ μλ κ²½μ° | ||
| if len(truck_weights) != 0 and sum + truck_weights[0] <= weight and truckNum + 1 <= bridge_length: | ||
| truck = truck_weights.popleft() # pop | ||
| onBridge.append((truck, time)) # λ€λ¦¬ μμ truckμ tuple μΆκ° | ||
| sum += truck # λ¬΄κ² μΆκ° | ||
| truckNum += 1 # 건λκ³ μλ νΈλ μΆκ° | ||
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| return time |
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,19 @@ | ||
| import sys | ||
| import heapq | ||
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| line = int(sys.stdin.readline().strip()) | ||
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| heap = [] | ||
| heapq.heapify(heap) | ||
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| for i in range(line): | ||
| data = list(map(int, sys.stdin.readline().strip().split())) | ||
| for s in data: | ||
| if len(heap) < line: | ||
| heapq.heappush(heap, s) | ||
| else: | ||
| if s > heap[0]: | ||
| heapq.heappop(heap) | ||
| heapq.heappush(heap, s) | ||
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| print(heap[0]) |
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,32 @@ | ||
| import sys | ||
| import heapq | ||
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| n, m = map(int, sys.stdin.readline().rstrip().split()) | ||
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| graph = [[] for _ in range(n+1)] | ||
| inDegree = [0 for _ in range(n+1)] | ||
| q = [] | ||
| answer = [] | ||
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| # μ λ ₯λ°μμ λ£κΈ° | ||
| for _ in range(m): | ||
| p1, p2 = map(int, sys.stdin.readline().rstrip().split()) | ||
| graph[p1].append(p2) # p1μ p2μ μ°κ²°λ λ¬Έμ | ||
| inDegree[p2] += 1 # κ°μ μΆκ° | ||
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| # μ§μ μ°¨μκ° 0μ΄λ©΄ νμ λ£κΈ° | ||
| for i in range(1, n+1): | ||
| if inDegree[i] == 0: | ||
| heapq.heappush(q, i) | ||
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| # answerμ λ£κ³ , κ°μ μ κ±° | ||
| while q: | ||
| prob = heapq.heappop(q) | ||
| answer.append(prob) | ||
| for i in graph[prob]: # κ°μ μ κ±° & μ§μ μ°¨μ 0μΈ κ²λ€ μ²λ¦¬ | ||
| inDegree[i] -= 1 | ||
| if inDegree[i] == 0: | ||
| heapq.heappush(q, i) | ||
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| for result in answer: | ||
| print(result, end=" ") |
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,80 @@ | ||
| #include <iostream> | ||
| #include <vector> | ||
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| using namespace std; | ||
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| struct Trie { | ||
| struct Node { | ||
| Node *children[10]{}; | ||
| bool isTerminal = false; | ||
| }; | ||
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| Node *root = new Node; | ||
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| bool insert(string &s) const { | ||
| auto cur = root; | ||
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| for (char ch: s) { | ||
| int digit = ch - '0'; | ||
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| if (!cur->children[digit]) { | ||
| cur->children[digit] = new Node(); | ||
| cur = cur->children[digit]; | ||
| continue; | ||
| } | ||
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| if (cur->children[digit]->isTerminal) { | ||
| return false; | ||
| } | ||
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| cur = cur->children[digit]; | ||
| } | ||
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| for (auto child: cur->children) { | ||
| if (child) { | ||
| return false; | ||
| } | ||
| } | ||
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| cur->isTerminal = true; | ||
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| return true; | ||
| } | ||
| }; | ||
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| int main() { | ||
| ios_base::sync_with_stdio(false); | ||
| cin.tie(nullptr); | ||
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| auto solve = []() { | ||
| auto trie = new Trie; | ||
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| int n; | ||
| cin >> n; | ||
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| vector<string> numbers(n); | ||
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| for (auto &number: numbers) { | ||
| cin >> number; | ||
| } | ||
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| for (auto number: numbers) { | ||
| if (!trie->insert(number)) { | ||
| cout << "NO\n"; | ||
| delete trie; | ||
| return; | ||
| } | ||
| } | ||
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| cout << "YES\n"; | ||
| }; | ||
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| int t; | ||
| cin >> t; | ||
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| while (t--) { | ||
| solve(); | ||
| } | ||
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| return 0; | ||
| } |
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,53 @@ | ||
| def solution(coin, cards): | ||
| a = set(cards[:len(cards) // 3]) | ||
| b = set() | ||
| t = len(cards) + 1 | ||
| r = 1 | ||
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| for i in range(len(cards) // 3 + 1, len(cards), 2): | ||
| c1, c2 = cards[i - 1], cards[i] | ||
| b.add(c1) | ||
| b.add(c2) | ||
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| removed = False | ||
| # νμ¬ κ°μ§κ³ μλ μΉ΄λ λͺ©λ‘ μ€ n + 1μ΄ κ°λ₯ν κ²½μ° νμΈ | ||
| for x in list(a): | ||
| if t - x in a: | ||
| a.remove(t - x) | ||
| a.remove(x) | ||
| removed = True | ||
| break | ||
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| if removed: | ||
| r += 1 | ||
| continue | ||
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| # μ½μΈμΌλ‘ κ΅νν΄μ μ»μ μ μλ μΉ΄λ μ€μμ n + 1μ΄ λλ κ²½μ°λ₯Ό μ°ΎμμΌ ν¨ | ||
| # μ½μΈμ΄ μμΌλ―λ‘ μ’ λ£ | ||
| if not coin: | ||
| break | ||
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| # `νμ¬ κ°κ³ μλ μΉ΄λ + μ»μ μ μλ μΉ΄λ` = n + 1μ΄ λλ κ²½μ°λ₯Ό νμΈ | ||
| for x in list(b): | ||
| if t - x in a: | ||
| a.remove(t - x) | ||
| b.remove(x) | ||
| removed = True | ||
| coin -= 1 | ||
| break | ||
| # λ§μ§λ§ λ°©λ²μΌλ‘, μ€μ§ κ΅νμΌλ‘ μ»μ μ μλ μΉ΄λ λͺ©λ‘ μ€μμ n + 1μ΄ λλ κ²½μ°λ₯Ό νμΈ | ||
| if not removed and coin >= 2: | ||
| for x in list(b): | ||
| if t - x in b: | ||
| b.remove(t - x) | ||
| b.remove(x) | ||
| removed = True | ||
| coin -= 2 | ||
| break | ||
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| # n + 1μ μ΄λ€ κ²½μ°μλ λͺ» λ§λ€λ©΄ μ’ λ£ | ||
| if not removed: | ||
| break | ||
| r += 1 | ||
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| return r |
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