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given string s, find all the permutation, each letter can be lower or…
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… upper case
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Atousa committed May 19, 2021
1 parent 70b75f2 commit 3a1f729
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102 changes: 102 additions & 0 deletions Recursion/LetterCasePermutation.java
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import java.util.ArrayList;
import java.util.List;

public class LetterCasePermutation {
// given a string s, each letter can be lower case or upper case to create another string

static List<String> result = new ArrayList<>();

/**
*
* @param s
* @param cur
* @param slate
* this version is with string and string is immutable, the space complexity is input space complexity (length of slate o(n) + implicit
* stack space from recursion o(n^2) since in each activation record we create an string 1+2+3+...+n and the output space complexity that
* would be 2^n .n.
* time complexity for the leaf nodes that are 2^n is constant since they dont do anything , for internal nodes , specifically the nodes
* above the leaf nodes that do majority of work will be 2^n * n since they create string size n . so (2^n .n)
*/
private static void letterCasePermutationHelper1(String s, int cur, String slate) {

if(cur == s.length()) {
result.add(slate);
return;
}

if(Character.isDigit(s.charAt(cur))){
letterCasePermutationHelper1(s,cur+1,slate+s.charAt(cur));
} else {
//Character c = Character.toLowerCase(s.charAt(cur));
letterCasePermutationHelper1(s,cur+1, slate + Character.toLowerCase(s.charAt(cur)));
//c = Character.toUpperCase(s.charAt(cur));
letterCasePermutationHelper1(s,cur+1,slate + Character.toUpperCase(s.charAt(cur)));
}
}

/**
*
* @param s
* @param cur
* @param slate
* space complexity is o(2^n . n + n ) and time complexity is 2^n . O(1)
*/
private static void letterCasePermutationHelper2(String s, int cur, char[] slate) {

if (cur == s.length()) {
result.add(new String(slate));
return;
}
if(Character.isDigit(s.charAt(cur))){
slate[cur] = s.charAt(cur);
letterCasePermutationHelper2(s,cur+1,slate);
} else {
slate[cur] = Character.toLowerCase(s.charAt(cur));
letterCasePermutationHelper2(s,cur+1, slate);
slate[cur] = Character.toUpperCase(s.charAt(cur));
letterCasePermutationHelper2(s,cur+1,slate);
}

}
private static void letterCasePermutationHelper3(String s, int cur, List<Character> slate2) {

if (cur == s.length()) {
StringBuilder sb = new StringBuilder();
for(char c : slate2)
sb.append(c);
result.add(sb.toString());
return;
}

if(Character.isDigit(s.charAt(cur))){
slate2.add(s.charAt(cur));
letterCasePermutationHelper3(s,cur+1,slate2);
slate2.remove(slate2.size()-1);
} else {
slate2.add(Character.toLowerCase(s.charAt(cur)));
letterCasePermutationHelper3(s,cur+1, slate2);
slate2.remove(slate2.size()-1);
slate2.add(Character.toUpperCase(s.charAt(cur)));
letterCasePermutationHelper3(s,cur+1,slate2);
slate2.remove(slate2.size()-1);
}

}

public static void letterCasePermutation(String s) {
//letterCasePermutationHelper1(s, 0,"");
// char[] slate = new char[s.length()];
// letterCasePermutationHelper2(s, 0,slate);
// System.out.println(result);
List<Character> slate2 = new ArrayList<>();
letterCasePermutationHelper3(s, 0,slate2);
System.out.println(result);

}

public static void main(String[] args) {
String s = "a1b2";
letterCasePermutation(s);
}

}

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