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[EstherKim97] WEEK 02 #737
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Original file line number | Diff line number | Diff line change |
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@@ -0,0 +1,33 @@ | ||
class Solution(object): | ||
def climbStairs(self, n): | ||
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import math | ||
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# First attempt to this question. | ||
# Get dividend and remainder of 2 steps & get all combinations & add one additional method for all 1 step combination | ||
# But how to get all combinations? => permutation | ||
# def climbStairs(self, n): | ||
# # 2 steps | ||
# two_steps = n // 2 | ||
# two_steps_remainder = n % 2 | ||
# total_steps = two_steps + two_steps_remainder | ||
# total_permu = math.factorial(total_steps) // (math.factorial(two_steps) * math.factorial(two_steps_remainder)) | ||
# total_permu += 1 | ||
# return total_permu | ||
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# Second method - n = 2x+y | ||
if n % 2 == 0: | ||
max = n //2 | ||
else: | ||
max = (n-1) // 2 | ||
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total_methods = 0 | ||
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for i in range(0, max+1): | ||
y = n - (2 * i) | ||
total_steps = i + y | ||
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total_permu = math.factorial(total_steps) // (math.factorial(i) * math.factorial(y)) | ||
total_methods += total_permu | ||
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return total_methods |
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Original file line number | Diff line number | Diff line change |
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@@ -0,0 +1,20 @@ | ||
class Solution(object): | ||
def isAnagram(self, s, t): | ||
character1 = [] | ||
character2 = [] | ||
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# put characters in character1 and character2 | ||
for i in s: | ||
character1.append(i) | ||
for i in t: | ||
character2.append(i) | ||
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# sort out the characters in alphabetical order | ||
character1.sort() | ||
character2.sort() | ||
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# compare each characters to see if they match (= anagram) | ||
if character1 == character2: | ||
return True | ||
else: | ||
return False |
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DP를 통해서 풀이하는 방법도 도전해보시면 좋을것 같습니다!