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[EstherKim97] WEEK 02 #737

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Dec 22, 2024
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33 changes: 33 additions & 0 deletions climbing-stairs/EstherKim97.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,33 @@
class Solution(object):
def climbStairs(self, n):

import math

# First attempt to this question.
# Get dividend and remainder of 2 steps & get all combinations & add one additional method for all 1 step combination
# But how to get all combinations? => permutation
# def climbStairs(self, n):
# # 2 steps
# two_steps = n // 2
# two_steps_remainder = n % 2
# total_steps = two_steps + two_steps_remainder
# total_permu = math.factorial(total_steps) // (math.factorial(two_steps) * math.factorial(two_steps_remainder))
# total_permu += 1
# return total_permu

# Second method - n = 2x+y
if n % 2 == 0:
max = n //2
else:
max = (n-1) // 2

total_methods = 0

for i in range(0, max+1):
y = n - (2 * i)
total_steps = i + y

total_permu = math.factorial(total_steps) // (math.factorial(i) * math.factorial(y))
total_methods += total_permu
Comment on lines +19 to +31
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DP를 통해서 풀이하는 방법도 도전해보시면 좋을것 같습니다!


return total_methods
20 changes: 20 additions & 0 deletions valid-anagram/EstherKim97.py
Original file line number Diff line number Diff line change
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class Solution(object):
def isAnagram(self, s, t):
character1 = []
character2 = []

# put characters in character1 and character2
for i in s:
character1.append(i)
for i in t:
character2.append(i)

# sort out the characters in alphabetical order
character1.sort()
character2.sort()

# compare each characters to see if they match (= anagram)
if character1 == character2:
return True
else:
return False
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