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p-senichenkov
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Dec 5, 2025
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За все задачи 9/10
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Вы добавили на HWProj только первую задачу, так что я смогу поставить баллы только за неё.
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| while (a >= 2) { | ||
| b[index] = a % 2; | ||
| a = a / 2; | ||
| ++index; | ||
| } | ||
| b[index] = a; // число будет записано задом наперед, но для палиндрома это не важно |
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Здесь не нужно отдельно рассматривать a < 2. Можно сразу писать цикл до нуля.
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| if (a < 0) { | ||
| a = a * -1; | ||
| } |
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Suggested change
| if (a < 0) { | |
| a = a * -1; | |
| } | |
| a = abs(a); |
| a = a * -1; | ||
| } | ||
| while (a / 10 != 0) { | ||
| s = s + (a % 10); |
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Suggested change
| s = s + (a % 10); | |
| s += (a % 10); |
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| while (a / 10 != 0) { | ||
| s = s + (a % 10); | ||
| a = a / 10; |
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Здесь тоже можно написать более естественное условие цикла.
| int check(int arr[], int n) { | ||
| for (int i = 1; i < n; ++i) { | ||
| if (arr[i] < arr[i - 1]) { | ||
| return 1; |
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Конвенционально делается наоборот: 1 -- это true, а 0 -- false. Чтобы не было таких проблем, лучше использовать stdbool.h
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