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Fix false positive for duplicate command definition inspection in if/…
…else
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,76 @@ | ||
| package nl.hannahsten.texifyidea.util | ||
|
|
||
| import com.intellij.psi.PsiElement | ||
| import com.intellij.psi.util.elementType | ||
| import nl.hannahsten.texifyidea.lang.commands.LatexGenericRegularCommand | ||
| import nl.hannahsten.texifyidea.psi.LatexCommands | ||
| import nl.hannahsten.texifyidea.psi.LatexNoMathContent | ||
| import nl.hannahsten.texifyidea.psi.LatexParameter | ||
| import nl.hannahsten.texifyidea.psi.LatexTypes | ||
| import nl.hannahsten.texifyidea.util.parser.firstParentOfType | ||
| import nl.hannahsten.texifyidea.util.parser.nextSiblingOfType | ||
| import nl.hannahsten.texifyidea.util.parser.parentOfType | ||
| import nl.hannahsten.texifyidea.util.parser.previousSiblingOfType | ||
|
|
||
| /** | ||
| * If the element is in an if/else construct | ||
| */ | ||
| fun isInConditionalBranch(element: PsiElement): Boolean { | ||
| // \ifthenelse{condition}{true}{false} | ||
| if (element.firstParentOfType<LatexParameter>()?.firstParentOfType<LatexCommands>()?.name == LatexGenericRegularCommand.IFTHENELSE.commandWithSlash) { | ||
| return true | ||
| } | ||
|
|
||
| // Check for an \if...\fi combination | ||
| return isPreviousConditionalStart(element) && isNextConditionalEnd(element) | ||
| } | ||
|
|
||
| /** | ||
| * If the next relevant command is a \fi | ||
| */ | ||
| private fun isNextConditionalEnd(current: PsiElement): Boolean { | ||
| return isEndConditional(nextConditionalCommand(current, searchBackwards = false) ?: return false) | ||
| } | ||
|
|
||
| /** | ||
| * If the previous relevant command is an \if | ||
| */ | ||
| private fun isPreviousConditionalStart(current: PsiElement): Boolean { | ||
| return isStartConditional(nextConditionalCommand(current, searchBackwards = true) ?: return false) | ||
| } | ||
|
|
||
| /** | ||
| * Next relevant command. There are many ways in which this does not work, but since this is just an inspection this is much safer than trying to parse user defined \if commands in the parser, which is impossiblee | ||
| */ | ||
| private fun nextConditionalCommand(element: PsiElement, searchBackwards: Boolean): PsiElement? { | ||
| var current = element.parentOfType(LatexNoMathContent::class) | ||
| while (current != null && !isConditional(current)) { | ||
| current = if (!searchBackwards) { | ||
| current.nextSibling?.nextSiblingOfType(LatexNoMathContent::class) | ||
| } | ||
| else { | ||
| current.prevSibling?.previousSiblingOfType(LatexNoMathContent::class) | ||
| } | ||
| } | ||
| return current | ||
| } | ||
|
|
||
| private fun isConditional(element: PsiElement): Boolean { | ||
| return isStartConditional(element) || isEndConditional(element) | ||
| } | ||
|
|
||
| private fun isStartConditional(rootElement: PsiElement): Boolean { | ||
| // To keep it simple, only look one level down | ||
| for (element in rootElement.children + listOf(rootElement)) { | ||
| if (element is LatexCommands && element.name?.startsWith("\\if") == true) return true | ||
| if (element.elementType == LatexTypes.START_IF) return true | ||
| } | ||
| return false | ||
| } | ||
|
|
||
| private fun isEndConditional(rootElement: PsiElement): Boolean { | ||
| for (element in rootElement.children + listOf(rootElement)) { | ||
| if (element.firstChild?.elementType in setOf(LatexTypes.ELSE, LatexTypes.END_IF)) return true | ||
| } | ||
| return false | ||
| } |
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