Remove sqrtOfTokens (#211)

contracts/math/Sqrt.sol

@@ -10,24 +10,6 @@ library Sqrt
   /// @notice The max possible value
   uint256 constant MAX_UINT = 2**256 - 1;
 
-  /**
-   * @notice Calculates sqrt(x/(10^18)^2)*10^18 with 10 decimals of precision.
-   * @dev Assumes 18 decimals (standard for tokens). 10 decimals of precision was choosen to
-   * be on-par with the Vyper implementation.
-   * Returns 0 when x < 10^26.
-   */
-  function sqrtOfTokens(
-    uint x
-  ) public pure
-    returns (uint y)
-  {
-    // Shift by 18 decimals squared, and leave 10 decimals for sqrt precision
-    y = x / 10**(18 + 18 - 10);
-    y = sqrt(y);
-    // Adjust for sqrt(10^10) (5) and *10^18
-    y = y.mul(10**(18-5));
-  }
-
   // Source: https://github.com/ethereum/dapp-bin/pull/50
   function sqrt(
     uint x

package.json

@@ -1,6 +1,6 @@
 {
   "name": "hardlydifficult-ethereum-contracts",
-  "version": "0.6.6",
+  "version": "0.6.7",
   "description": "A collection of reusable contracts and Javascript helpers for Ethereum.",
   "scripts": {
     "build": "npm run compile",

test/math/sqrtNumbersArray.js

@@ -156,22 +156,6 @@ contract("math / sqrtNumbersArray", () => {
 
   for (let i = numbers.length - 1; i >= 0; i--) {
     const x = numbers[i];
-    let sqrtOfTokensResult = new BigNumber(x)
-      .div(new BigNumber(10).pow(8))
-      .dp(0) // we expect to lose 8 decimals before the sqrt
-      .div(new BigNumber(10).pow(36 - 8))
-      .sqrt()
-      .times(new BigNumber(10).pow(18));
-
-    it(`sqrtOfTokens(${x.toFixed()}) ~= ${sqrtOfTokensResult.toExponential(
-      2
-    )})`, async () => {
-      sqrtOfTokensResult = sqrtOfTokensResult.dp(0);
-      const contractRes = new BigNumber(
-        await contract.sqrtOfTokens(x.toFixed())
-      );
-      checkBounds(sqrtOfTokensResult, contractRes, true);
-    });
 
     let sqrtResult = new BigNumber(x).sqrt();
     it(`sqrt(${x.toFixed()}) ~= ${sqrtResult.toExponential(2)}`, async () => {