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Algorithms

You will attached my solutions to test algorithm in Java

Algo 1

You are given N counters, initially set to 0, and you have two possible operations on them:

  • increase(X) − counter X is increased by 1,
  • max counter − all counters are set to the maximum value of any counter.

A non-empty array A of M integers is given. This array represents consecutive operations:

  • if A[K] = X, such that 1 ≤ X ≤ N, then operation K is increase(X), max counter − all counters are set to the maximum value of any counter.
  • if A[K] = N + 1 then operation K is max counter.

For example, given integer N = 5 and array A such that:

  • A[0] = 3 A[1] = 4 A[2] = 4 A[3] = 6 A[4] = 1 A[5] = 4 A[6] = 4

the values of the counters after each consecutive operation will be:

  • (0, 0, 1, 0, 0)
  • (0, 0, 1, 1, 0)
  • (0, 0, 1, 2, 0)
  • (2, 2, 2, 2, 2)
  • (3, 2, 2, 2, 2)
  • (3, 2, 2, 3, 2)
  • (3, 2, 2, 4, 2)

The goal is to calculate the value of every counter after all operations. Write a function:

class Solution { public int[] solution(int N, int[] A); }

hat, given an integer N and a non-empty array A consisting of M integers, returns a sequence of integers representing the values of the counters. Result array should be returned as an array of integers. for example given :

  • A[0] = 3 A[1] = 4 A[2] = 4 A[3] = 6 A[4] = 1 A[5] = 4 A[6] = 4

the function should return [3, 2, 2, 4, 2], as explained above.

Write an efficient algorithm for the following assumptions:

  • N and M are integers within the range [1..100,000];
  • each element of array A is an integer within the range [1..N + 1].

Algo2

You have to climb up a ladder. The ladder has exactly N rungs, numbered from 1 to N. With each step, you can ascend by one or two rungs. More precisely:

  • with your first step you can stand on rung 1 or 2
  • if you are on rung K, you can move to rungs K + 1 or K + 2,
  • finally you have to stand on rung N.

your task is to count the number of different ways of climbing to the top of the ladder For example, given N = 4, you have five different ways of climbing, ascending by:

  • 1, 1, 1 and 1 rung,
  • 1, 1 and 2 rungs,
  • 1, 2 and 1 rung,
  • 2, 1 and 1 rungs, and
  • 2 and 2 rungs.

Given N = 5, you have eight different ways of climbing, ascending by:

  • 1, 1, 1, 1 and 1 rung,
  • 1, 1, 1 and 2 rungs,
  • 1, 1, 2 and 1 rung,
  • 1, 2, 1 and 1 rung,
  • 1, 2 and 2 rungs,
  • 2, 1, 1 and 1 rungs,
  • 2, 1 and 2 rungs, and
  • 2, 2 and 1 rung.

The number of different ways can be very large, so it is sufficient to return the result modulo 2P, for a given integer P. Write a function:

class Solution { public int[] solution(int[] A, int[] B); }

that, given two non-empty arrays A and B of L integers, returns an array consisting of L integers specifying the consecutive answers; position I should contain the number of different ways of climbing the ladder with A[I] rungs modulo 2B[I]. For example, given L = 5 and:

  • A[0] = 4 B[0] = 3
  • A[1] = 4 B[1] = 2
  • A[2] = 5 B[2] = 4
  • A[3] = 5 B[3] = 3
  • A[4] = 1 B[4] = 1

the function should return the sequence [5, 1, 8, 0, 1], as explained above

Write an efficient algorithm for the following assumptions:

  • L is an integer within the range [1..50,000];
  • each element of array A is an integer within the range [1..L];
  • each element of array B is an integer within the range [1..30].

Algo3

For a given array A of N integers and a sequence S of N integers from the set {−1, 1}, we define val(A, S) as follows:

val(A, S) = |sum{ A[i]*S[i] for i = 0..N−1 }|

(Assume that the sum of zero elements equals zero.)

For a given array A, we are looking for such a sequence S that minimizes val(A,S). Write a function:

class Solution { public int solution(int[] A); }

that, given an array A of N integers, computes the minimum value of val(A,S) from all possible values of val(A,S) for all possible sequences S of N integers from the set {−1, 1}. For example, given array:

  • A[0] = 1 A[1] = 5 A[2] = 2 A[3] = -2

your function should return 0, since for S = [−1, 1, −1, 1], val(A, S) = 0, which is the minimum possible value.

Write an efficient algorithm for the following assumptions :

  • N is an integer within the range [0..20,000];
  • each element of array A is an integer within the range [−100..10

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