Set

This is a web-app for Facebook and VK, which is based on a popular card game SET. (VK is a social network, russian analogue of Facebook, https://vk.com)

You can find working versions of the Set game on both Facebook (here) and VK (here). In this repository we have two separated branches for two different platforms.

Please note! that this game was initially designed for Russian network. Therefore, VK version is more developed (for example, in Facebook version I do not have a feature of displaying profile pictures of top-players. However, Facebook API is not very different from VK's one so I plan to add it soon)

Also, the game is not translated yet, but you can always read the rules here.

How does that work?

This is an iframe-app (a web-site, in fact) so I used HTML+CSS and JavaScript mainly to develop it.

VK / Facebook APIs were used to get users' info (name, id, profile pic).

Users' data and best scores are stored at MySQL db, so some PHP was used to display a table with top players.

AJAX helped me to implement data exchange between JS and PHP.

The game has two modes: classic and a speed one (where you have only 2 minutes to sind sets).

How do I recognize a set?

Each card has 4 properties, each property takes 3 different values:

• color - green, red or purple
• form of the figure - ellipse, rhombus or a wave
• number of figures - one, two or three
• filling - filled, shaded or empty

I encoded cards in ternary code - from 0000 to 2222 - 81 unique cards in total.

// fill the list with cards (81 unique cards)
for(var i = 0; i <= 2; i++){
    for(var j = 0; j <= 2; j++){
        for(var k = 0; k <= 2; k++){
            for(var l = 0; l <= 2; l++){
                cards.push(String(i) + String(j) + String(k) + String(l));
            }
        }
    }
}

So now to check whether three cards make up a set we just need to check if the sum of their codes for each property is divided by 3.

function check_if_set(first, second, third)
{
    for (var m = 0; m <= 3; m++)  // for each of 4 properties
    {
        if ((+first[m] + +second[m] + +third[m]) % 3 != 0)
        {
            return false;
        }
    }
    return true;
}

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You are very welcome with your commits and suggestions

You can always contact me via email: foggyjandjane@gmail.com