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Number formater #34
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Number formater #34
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Kern046
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Dec 15, 2018
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Il faut que tu aères beaucoup plus ton code et que tu respectes les guidelines sur l'indentation, le respect des accolades etc..
Sinon la méthode formatNumber est beaucoup trop grosse et complexe il faudrait que tu la découpes en plusieurs fonctions plus petites
| } | ||
| if(decimalNumber <= decimalSize) { | ||
| numberLength = newNumber.toString().length-decimalNumber; | ||
| } |
| if(decimalNumber <= decimalSize) { | ||
| numberLength = newNumber.toString().length-decimalNumber; | ||
| } | ||
| else { |
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| else { | |
| } else { |
| decimalNumber=decimalSize; | ||
| numberLength= newNumber.toString().length-decimalNumber; | ||
| } | ||
| } |
| numberTemp=Math.floor(numberTemp); | ||
|
|
||
| cpt = 0; | ||
| while (cpt<numberLength) |
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remonte l'accolage d'une ligne
| :" ") | ||
| :"") | ||
| ; | ||
| (Math.floor(currentNumberOfTimeUnit)>0||stringSize>0)?stringSize++:cpt=cpt; |
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Usine à gaz de la mort sur ces lignes, aère ton code :)
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