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Nicola Ferru Aka NFVblog authored and Nicola Ferru Aka NFVblog committed Jul 23, 2024
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285 changes: 144 additions & 141 deletions Primo anno/Fisica/formulario/formulario.aux
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56 changes: 31 additions & 25 deletions Primo anno/Fisica/formulario/formulario.log
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This is pdfTeX, Version 3.141592653-2.6-1.40.26 (TeX Live 2024/Arch Linux) (preloaded format=pdflatex 2024.4.21) 1 JUN 2024 22:35
This is pdfTeX, Version 3.141592653-2.6-1.40.26 (TeX Live 2024/Arch Linux) (preloaded format=pdflatex 2024.7.14) 22 JUL 2024 13:48
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File: img/scalare-eps-converted-to.pdf Graphic file (type pdf)
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[11 <./img/scalare-eps-converted-to.pdf>]

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Capitolo 2.

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Expand All @@ -1364,7 +1364,7 @@ Overfull \vbox (8.84552pt too high) has occurred while \output is active []

[29] (./img/onde.tikz) [30]
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Expand All @@ -1386,14 +1386,20 @@ LaTeX Font Warning: Size substitutions with differences

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2 changes: 1 addition & 1 deletion Primo anno/Fisica/formulario/formulario.out
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22 changes: 17 additions & 5 deletions Primo anno/Fisica/formulario/formulario.tex
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Expand Up @@ -281,7 +281,7 @@ \section{Moto circolare uniforme}
\label{sec:velang}
\begin{equation}
\label{eq:velang}
\omega=\sfrac{2\pi_{rad}}{T}=2\pi\cdot v
\omega=\sfrac{2\pi_{rad}}{T}=2\pi\cdot f
\end{equation}
\begin{equation}
\label{eq:Velang}
Expand All @@ -291,6 +291,18 @@ \section{Moto circolare uniforme}
$\Delta\alpha =$ angolo spezzato al centro
\end{defi}

\subsubsection{Sostituzioni e formule inverse}
\label{sec:sostform}

\begin{eqnarray}
\label{eq:sostform}
a_c=\omega^2r; & v=\frac{2\pi \cdot r}{T};
& \omega=\frac{v}{r}\\
r=\frac{V\cdot T}{2\cdot\pi}; & r=\frac{V}{\omega};
& r=\frac{v^2}{a_c}\\
r=\frac{a_c}{\omega^2}; & T=\frac{2\pi r}{v};
& T=\frac{2\pi}{\omega}\\
\end{eqnarray}
\subsection{Energia cinetica totale}
\label{sec:encintot}

Expand Down Expand Up @@ -328,7 +340,7 @@ \subsection{Forza centripeta e centrifuga}
\label{sec:periodocentuni}
\begin{equation}
\label{eq:periodocentuni}
t=\frac{1}{f}
T=\frac{1}{f}
\end{equation}
\end{multicols}
Dato che le due formule danno due valori uno opposto all'altro possiamo dire senza ombra di dubbio che:
Expand Down Expand Up @@ -535,7 +547,7 @@ \section{Moto Parabolico (Moto del proiettile)}
\end{equation*}
Tramite $v_{0x}^2$ e $v_{0y}^2$ è possibile essere anche utilizzato per ricavare la tangente:
\begin{equation*}
\tan(\alpha)=\frac{v_{0x}}{v_{0y}}
\tan(\alpha)=\frac{v_{0y}}{v_{0x}}
\end{equation*}
L'equazione parametrica base invece è definita da due cordinete (\textit{x} e \textit{y}):
\begin{equation}
Expand Down Expand Up @@ -879,7 +891,7 @@ \subsubsection{Equazione vettoriale del centro di massa}
\end{description}
Tieni a mente che molti dei carpi che potresti deve trattare sono dettati di assi, punti o piani di {\color{red}simmetria}, uniti per individuare il centro di massa (in quel punto, lungo quella linea, \dots).

\subsubsection{Accelerazione del centro di massa (di un sistema di particelle)}
\subsubsection{Accelerazione el centro di massa (di un sistema di particelle)}
\label{sec:accdelcentrodimass}
\begin{equation}
\label{eq:accdelcentrodimass}
Expand Down Expand Up @@ -1204,7 +1216,7 @@ \subsection{Momenti di inerzia da ricordare}
\end{equation}
\end{multicols}

\section{Equazione del moto di un oscillazione armonico}
\section{Equazione del moto di un oscillazione armonico (moto armonico)}
\label{sec:eqdelmotodiunoscarm}

\begin{equation}
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