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p-senichenkov
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Dec 14, 2025
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| case ']': | ||
| if (get(&ScobStruct, '[')) | ||
| pop(&ScobStruct); | ||
| else | ||
| flag = 0; | ||
| break; | ||
| case ')': | ||
| if (get(&ScobStruct, '(')) | ||
| pop(&ScobStruct); | ||
| else | ||
| flag = 0; | ||
| break; | ||
| case '}': | ||
| if (get(&ScobStruct, '{')) | ||
| pop(&ScobStruct); | ||
| else | ||
| flag = 0; | ||
| break; |
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Надо сделать так, чтобы не повторять одно и то же для разных видов скобок. Как раз для этого и используется стек.
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Надо задачу решать полностью в одной ветке. А то комменатрии теряются
| flag = 0; | ||
| break; | ||
| default: | ||
| if (InputString[i] == '(' || InputString[i] == '[' || InputString[i] == '{') |
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Нет, вот так точно не делается. Если используете switch, то надо все варианты прописать как case. Понятно, что хочется pattern matching, но в C его нет, и не должно быть (за счёт того, что switch работает только с целочисленными типами).
Подсказка: switch умеет проваливаться, и этим надо воспользоваться.
| #include <stdlib.h> | ||
| #include "stack.h" | ||
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| void push(stack *begin, char c) { |
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Хорошо бы ещё функции инициализации и очистки стека сделать. Но это не критично.
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