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Operator Overloading
Trin Wasinger edited this page Nov 14, 2024
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1 revision
An expression x op y
is evaluated as follows:
- if x is a primitive and y is an object with op,
y[op](x, y)
- if x is an object with op and y is a primitive,
x[op](x, y)
- if y has op and is a subclass of x,
y[op](x,y)
- if x has op and is a subclass of y,
x[op](x,y)
- if x has op,
x[op](x,y)
- if y has op,
y[op](x,y)
- else
builtin(x,y)