Skip to content
Open
Changes from all commits
Commits
File filter

Filter by extension

Filter by extension

Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
47 changes: 47 additions & 0 deletions Easy/flipping-image.cpp
Original file line number Diff line number Diff line change
@@ -0,0 +1,47 @@
/* LEETCODE PROBLEM: 832
Flipping an Image

https://leetcode.com/problems/flipping-an-image/

Given an n x n binary matrix image, flip the image horizontally, then invert it, and return the resulting image.
To flip an image horizontally means that each row of the image is reversed.
For example, flipping [1,1,0] horizontally results in [0,1,1].
To invert an image means that each 0 is replaced by 1, and each 1 is replaced by 0.
For example, inverting [0,1,1] results in [1,0,0].

Example 1:
Input: image = [[1,1,0],[1,0,1],[0,0,0]]
Output: [[1,0,0],[0,1,0],[1,1,1]]
Explanation: First reverse each row: [[0,1,1],[1,0,1],[0,0,0]].
Then, invert the image: [[1,0,0],[0,1,0],[1,1,1]]
*/
class Solution {
public:
vector<vector<int>> flipAndInvertImage(vector<vector<int>>& image) {

for(int i=0;i<image.size();i++)
{
int start=0;
int end=image[i].size()-1;
while(start<end)
{
swap(image[i][start],image[i][end]);
start++;
end--;
}
for(int j=0;j<image[i].size();j++)
{
if(image[i][j]==0)
{
image[i][j]=1;
}
else
{
image[i][j]=0;
}
}
}

return image;
}
};