Answer

arraySolution.js

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+/*Write a function that accepts an array of 10 integers (between 0 and 9), that returns a string of those numbers in the form of a phone number.
+
+Example
+createPhoneNumber([1, 2, 3, 4, 5, 6, 7, 8, 9, 0]) // => returns "(123) 456-7890"
+The returned format must be correct in order to complete this challenge.
+
+Don't forget the space after the closing parentheses! 
+
+
+const chai = require("chai");
+const assert = chai.assert;
+chai.config.truncateThreshold=0;
+
+describe("Create Phone Number", () => {
+  it("Fixed tests", () => {
+    assert.strictEqual(createPhoneNumber([1, 2, 3, 4, 5, 6, 7, 8, 9, 0]), "(123) 456-7890");
+    assert.strictEqual(createPhoneNumber([1, 1, 1, 1, 1, 1, 1, 1, 1, 1]), "(111) 111-1111");
+    assert.strictEqual(createPhoneNumber([1, 2, 3, 4, 5, 6, 7, 8, 9, 0]), "(123) 456-7890");
+  });
+}); */
+
+
+function createPhoneNumber(numbers){
+
+    return `(${numbers[0]}${numbers[1]}${numbers[2]}) ${numbers[3]}${numbers[4]}${numbers[5]}-${numbers[6]}${numbers[7]}${numbers[8]}${numbers[9]}`
+  }
+

booleanArraySolution.js

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+/*Consider an array/list of sheep where some sheep may be missing from their place. We need a function that counts the number of sheep present in the array (true means present).
+
+For example,
+
+[true,  true,  true,  false,
+  true,  true,  true,  true ,
+  true,  false, true,  false,
+  true,  false, false, true ,
+  true,  true,  true,  true ,
+  false, false, true,  true]
+The correct answer would be 17.
+
+Hint: Don't forget to check for bad values like null/undefined*/
+
+function countSheeps(arrayOfSheep) {
+    const present = arrayOfSheep.filter(sheep => sheep);
+    return present.length;
+  }
+

whileLoopSolution.js

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+//loop solution for Task
+/*Complete function padIt, which accepts 2 parameters:
+
+str: a string representing the string to pad. We will pad it with "*" symbols on its left side and on its right side.
+n: a number indicating how many times to pad the string.
+Behaviour
+You need to write a loop statement within the function that loops n times. Each time through the loop it will add one * to str, alternating on which side it is padded: the first time will add a * to the left side of str, the second time will add a * to the right side, and so on.
+
+Finally, return the padded string.*/
+
+
+
+function padIt(str,n){
+    //declaring function passing in parameters
+    while(n>0){
+        //while statement that "while" variable "n" is more than 0 function will run//
+      if(n%2 === 0) {
+        str = str + "*";
+        //if "n" is divisible by 2 and equals 0 string gets a "*" added to the right
+      }else{
+        str = "*" + str;
+      }//else string add to left
+      n --;
+      //confused about this one
+    }
+    return str;
+    //return string to orginal postion (able to be ran again)
+  }