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chernishev
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2_StyleGid/Tickets
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бинарные файлы не коммитим
chernishev
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Oct 27, 2025
2_StyleGid/luckyTickets.c
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| int main(void) | ||
| { | ||
| printf("Введите число от 0 до 27:\t"); |
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это не "подсчётом числа билетов с заданной суммой трёх цифр"
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p-senichenkov
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Dec 13, 2025
2_StyleGid/luckyTickets.c
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| for (int z1 = 0; z1 <= 9; z1++) { // первая цифра | ||
| for (int z2 = 0; z2 <= 9; z2++) { // вторая цифра | ||
| for (int z3 = 0; z3 <= 9; z3++) { // третья цифра | ||
| if ((z1 <= z2) && (z2 <= z3)) { // чтобы не было повторов (мы же сочетания считаем) |
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Чтобы не было повторов, надо правильно написать условие цикла (т. е. инициализировать переменные не нулём).
Но это неправильный подход. Нам как раз нужно считать повторы. Так программа сожжёт немножко немножко больше электричества, но зато код станет сильно проще.
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| for (int summ = 1; summ <= 27; summ++) { // а теперь не берем нулевую сумму | ||
| fullCount += oneSummCount[summ] * oneSummCount[summ]; |
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Это можно сделать сразу при подсчёте сумм. Не надо делать лишний проход.
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не совсем понимаю как, если мы сначала добавляем всё, а потом возводи в квадрат
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Моё решение задачи про счастливые билетики.