K closest points to origin

https://leetcode.com/problems/k-closest-points-to-origin

Implementation :

class Solution {
    class Point {
        double distance;
        int index;
        Point(double distance, int index) {
            this.distance = distance; this.index = index;
        }
    }
    public int[][] kClosest(int[][] points, int K) {
       List<Point> list = new ArrayList<>(); 
       for(int i = 0; i < points.length; i++) {
           int[] point = points[i];
           double distance = Math.sqrt(point[0] * point[0] + point[1] * point[1]);
           list.add(new Point(distance, i));
       }
       Collections.sort(list, (p1, p2) -> Double.compare(p1.distance, p2.distance));
       int[][] result = new int[K][]; 
       for(int i = 0; i < K; i++) {
           result[i] = points[list.get(i).index];
       } 
        return result;
    }
}

Note : The most important part was getting the comparator method right, Double.compare(p1.distance, p2.distance)

Variant : If two points are exact same distance apart(there is tie) then choose the co-ordinate with least x value.

public class Solution {
    class Point {
        int x;
        int y;
        double distance;
            
        Point(int x, int y, double distance) {
            this.x = x;
            this.y = y;
            this.distance = distance;
        }
    }
    public int[][] kClosest(int[][] points, int k) {
        int[][] result = new int[k][2];
        List<Point> pointsList = new ArrayList<Point>();
        for(int[] point : points) {
            double distance = Math.sqrt((point[0] * point[0]) + (point[1] * point[1]));
            pointsList.add(new Point(point[0], point[1], distance));
        }
        Collections.sort(pointsList , (p1, p2) -> {
        	if(p1.distance == p2.distance) {
        		return p1.x - p2.x;
        		/** Tie Situation : if question is looking for nearest point with x value, 
                regardless of whether x value is positive or negative
                then return Math.abs(p1.x) - Math.abs(p2.x); **/
        	} 
        	else
                return Double.compare(p1.distance, p2.distance);
        });
        for(int i = 0; i < k; i++) {
            result[i] = new int[]{pointsList.get(i).x, pointsList.get(i).y};
        }
        return result;
    }
}