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solution(cpp): 122. Best Time to Buy and Sell Stock II
122. Best Time to Buy and Sell Stock II - C++
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You are given an integer array prices where prices[i] is the price of a given stock on the ith day. | ||
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On each day, you may decide to buy and/or sell the stock. You can only hold at most one share of the stock at any time. However, you can buy it then immediately sell it on the same day. | ||
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Find and return the maximum profit you can achieve. | ||
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**Example 1:** | ||
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Input: prices = [7,1,5,3,6,4] | ||
Output: 7 | ||
Explanation: Buy on day 2 (price = 1) and sell on day 3 (price = 5), profit = 5-1 = 4. | ||
Then buy on day 4 (price = 3) and sell on day 5 (price = 6), profit = 6-3 = 3. | ||
Total profit is 4 + 3 = 7. | ||
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Example 2: | ||
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Input: prices = [1,2,3,4,5] | ||
Output: 4 | ||
Explanation: Buy on day 1 (price = 1) and sell on day 5 (price = 5), profit = 5-1 = 4. | ||
Total profit is 4. | ||
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Example 3: | ||
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Input: prices = [7,6,4,3,1] | ||
Output: 0 | ||
Explanation: There is no way to make a positive profit, so we never buy the stock to achieve the maximum profit of 0. | ||
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Constraints: | ||
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1 <= prices.length <= 3 * 104 | ||
0 <= prices[i] <= 104 | ||
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Medium/122. Best Time to Buy and Sell Stock II/solution.cpp
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class Solution { | ||
public: | ||
int maxProfit(vector<int>& prices) { | ||
int maxProfit = 0; | ||
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for (int i = 1; i < prices.size(); i++) { | ||
if (prices[i] > prices[i - 1]) { | ||
maxProfit += prices[i] - prices[i - 1]; | ||
} | ||
} | ||
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return maxProfit; | ||
} | ||
}; |