#
Power Of Numbers Practice
#Given a number and its reverse. Find that number raised to the power of its own reverse.
#Note: As answers can be very large, print the result modulo 109 + 7.
long long check(int n,int r)
{
//int mod=1e9+7;
if(r==0)
return 1;
if(n==0)
return 0;
if(r%2==0)
{
long long ans=check(n,r/2);
return (ans%mod *ans%mod)%mod;
}
else
{
long long ans=check(n,(r-1)/2);
return(ans%mod *ans%mod *n%mod)%mod;
}
}