Skip to content

Commit

Permalink
Sync LeetCode submission Runtime - 136 ms (60.63%), Memory - 18.9 MB …
Browse files Browse the repository at this point in the history
…(14.92%)
  • Loading branch information
jimit105 committed Jan 13, 2025
1 parent c7d6865 commit 3d97069
Show file tree
Hide file tree
Showing 2 changed files with 72 additions and 0 deletions.
47 changes: 47 additions & 0 deletions 3455-minimum-length-of-string-after-operations/README.md
Original file line number Diff line number Diff line change
@@ -0,0 +1,47 @@
<p>You are given a string <code>s</code>.</p>

<p>You can perform the following process on <code>s</code> <strong>any</strong> number of times:</p>

<ul>
<li>Choose an index <code>i</code> in the string such that there is <strong>at least</strong> one character to the left of index <code>i</code> that is equal to <code>s[i]</code>, and <strong>at least</strong> one character to the right that is also equal to <code>s[i]</code>.</li>
<li>Delete the <strong>closest</strong> character to the <strong>left</strong> of index <code>i</code> that is equal to <code>s[i]</code>.</li>
<li>Delete the <strong>closest</strong> character to the <strong>right</strong> of index <code>i</code> that is equal to <code>s[i]</code>.</li>
</ul>

<p>Return the <strong>minimum</strong> length of the final string <code>s</code> that you can achieve.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">s = &quot;abaacbcbb&quot;</span></p>

<p><strong>Output:</strong> <span class="example-io">5</span></p>

<p><strong>Explanation:</strong><br />
We do the following operations:</p>

<ul>
<li>Choose index 2, then remove the characters at indices 0 and 3. The resulting string is <code>s = &quot;bacbcbb&quot;</code>.</li>
<li>Choose index 3, then remove the characters at indices 0 and 5. The resulting string is <code>s = &quot;acbcb&quot;</code>.</li>
</ul>
</div>

<p><strong class="example">Example 2:</strong></p>

<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">s = &quot;aa&quot;</span></p>

<p><strong>Output:</strong> <span class="example-io">2</span></p>

<p><strong>Explanation:</strong><br />
We cannot perform any operations, so we return the length of the original string.</p>
</div>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
<li><code>1 &lt;= s.length &lt;= 2 * 10<sup>5</sup></code></li>
<li><code>s</code> consists only of lowercase English letters.</li>
</ul>
25 changes: 25 additions & 0 deletions 3455-minimum-length-of-string-after-operations/solution.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,25 @@
# Approach 1: Using Hash Map

# n = len(s), k = len(character set)
# Time: O(n)
# Space: O(k) = O(1)

from collections import Counter

class Solution:
def minimumLength(self, s: str) -> int:
char_freq = Counter(s)

delete_count = 0

for freq in char_freq.values():
if freq % 2 == 1:
# If frequency is odd, delete all except one
delete_count += freq - 1
else:
# If frequency is even, delete all except two
delete_count += freq - 2

# Return the minimum length after deletions
return len(s) - delete_count

0 comments on commit 3d97069

Please sign in to comment.