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[#70] fix: 기사 중복 배차 동시성 문제 해결 및 DB 무결성 적용 #71

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Merged
Leesowon merged 1 commit into from
Feb 25, 2026
Merged

[#70] fix: 기사 중복 배차 동시성 문제 해결 및 DB 무결성 적용 #71

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2 changes: 1 addition & 1 deletion db-migrations/20260215_fix_duplicate_assigned_dispatches.sql
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Original file line number Diff line number Diff line change
Expand Up @@ -123,7 +123,7 @@ BEGIN
AND d.status = 'ASSIGNED'
AND d.active = true
WHERE t.dispatch_status = 'DISPATCH'
AND d.dispatch_id IS NULL;
AND d.id IS NULL;

IF inconsistent_count > 0 THEN
RAISE NOTICE 'Found % transporters with inconsistent dispatch_status', inconsistent_count;
Expand Down
15 changes: 8 additions & 7 deletions db-migrations/20260215_pre_migration_check.sql
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Original file line number Diff line number Diff line change
Expand Up @@ -17,8 +17,8 @@ SELECT
t.name as transporter_name,
t.phone,
t.dispatch_status,
COUNT(d.dispatch_id) as assigned_count,
STRING_AGG(d.dispatch_id::text, ', ' ORDER BY d.assigned_at DESC) as dispatch_ids,
COUNT(d.id) as assigned_count,
STRING_AGG(d.id::text, ', ' ORDER BY d.assigned_at DESC) as dispatch_ids,
STRING_AGG(d.assigned_at::text, ', ' ORDER BY d.assigned_at DESC) as assigned_times,
STRING_AGG(d.charge::text, ', ' ORDER BY d.assigned_at DESC) as charges
FROM dispatch d
Expand All @@ -27,8 +27,8 @@ WHERE d.status = 'ASSIGNED'
AND d.active = true
AND d.transporter_id IS NOT NULL
GROUP BY t.transporter_id, t.name, t.phone, t.dispatch_status
HAVING COUNT(d.dispatch_id) > 1
ORDER BY COUNT(d.dispatch_id) DESC, t.transporter_id;
HAVING COUNT(d.id) > 1
ORDER BY COUNT(d.id) DESC, t.transporter_id;

-- ================================================================
-- Check 2: 중복 배차 통계
Expand Down Expand Up @@ -64,8 +64,9 @@ SELECT
'1. Has ASSIGNED dispatch but status is EMPTY' as inconsistency_type,
t.transporter_id,
t.name,

t.dispatch_status,
COUNT(d.dispatch_id) as assigned_dispatch_count
COUNT(d.id) as assigned_dispatch_count
FROM transporters t
JOIN dispatch d ON t.transporter_id = d.transporter_id
WHERE d.status = 'ASSIGNED'
Expand All @@ -87,7 +88,7 @@ LEFT JOIN dispatch d ON t.transporter_id = d.transporter_id
AND d.status = 'ASSIGNED'
AND d.active = true
WHERE t.dispatch_status = 'DISPATCH'
AND d.dispatch_id IS NULL;
AND d.id IS NULL;

-- ================================================================
-- Check 4: 중복 배차 상세 정보 (샘플 5건)
Expand All @@ -96,7 +97,7 @@ SELECT
'=== Sample Duplicate Dispatches (Top 5) ===' as check_title;

SELECT
d.dispatch_id,
d.id,
d.transporter_id,
t.name as transporter_name,
d.status,
Expand Down