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Fix FAQ: block params shadow outer lvars #2851

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Fix FAQ: block params shadow outer lvars #2851

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13 changes: 7 additions & 6 deletions en/documentation/faq/4/index.md
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Original file line number Diff line number Diff line change
Expand Up @@ -361,19 +361,20 @@ the method is invoked. It is evaluated using the scope of the method.

### How do I pass arguments to a block?

Typically, arguments are passed to a block using `yield` (or an iterator
that calls `yield`), or by using the `Proc.call` method.
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I had previously just moved this paragraph to the top, but it should also be altered to use the appropriate syntax to indicate an instance method on Proc. I prefer the # syntax, but this should use whichever is most consistent with other parts of this FAQ.

Suggested change
that calls `yield`), or by using the `Proc.call` method.
that calls `yield`), or by using the `proc.call` method.
Suggested change
that calls `yield`), or by using the `Proc.call` method.
that calls `yield`), or by using the `Proc#call` method.


The formal parameters of a block appear between vertical bars at the start
of the block:

~~~
proc {|a, b| a <=> b }
~~~

These parameters are actually local variables. If an existing local variable
of the same name exists when the block executes, that variable will be
modified by the call to the block. This may or may not be a good thing.

Typically, arguments are passed to a block using `yield` (or an iterator that
calls `yield`), or by using the `Proc.call` method.
These parameters are actually local variables, scoped to that block. If a
local variable with the same name as a block parameter exists when the
block is defined, that outer variable will be "shadowed" (hidden) inside the
block by the block parameter. This may or may not be a good thing.

### Why did my object change unexpectedly?

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