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Update Merge Sort Tree & Create HLD #24

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Oct 8, 2020
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51 changes: 51 additions & 0 deletions hld.cpp
Original file line number Diff line number Diff line change
@@ -0,0 +1,51 @@
constexpr int MAXN = 111111;

vector<int> graph[MAXN];
int par[MAXN], sub[MAXN], dep[MAXN];
void dfs(int now, int before) {
par[now] = before;
sub[now] = 1;
for(int nxt: graph[now]) if (nxt != before)
{
dep[nxt] = dep[now] + 1;
dfs(nxt, now);
sub[now] += sub[nxt];
}
}
vector<int> chain[MAXN];
int wt_chain[MAXN], in_chain[MAXN], ps[MAXN], occ = 0;
void hld(int now, int before, int cur_chain) {
wt_chain[now] = cur_chain;
in_chain[now] = chain[cur_chain].size();
chain[cur_chain].push_back(now);
int hvy = -1;
for (int nxt: graph[now]) if (nxt != before)
{
if (hvy==-1 || sub[nxt] > sub[hvy]) hvy = nxt;
}
if (hvy != -1) hld(hvy, now, cur_chain);
for (int nxt: graph[now]) if (nxt != before)
{
if (nxt != hvy) hld(nxt, now, nxt);
}
if (cur_chain == now)
{
ps[cur_chain] = occ;
occ += chain[cur_chain].size();
}
}
//위치 공식 : ps[wt_chain[a]]+in_chain[a]
int get_lca(int a, int b)
{
while(wt_chain[a] != wt_chain[b])
{
if (dep[wt_chain[a]] > dep[wt_chain[b]])
a = par[wt_chain[a]];
else
b = par[wt_chain[b]];
}
if (in_chain[a] > in_chain[b])
return b;
else
return a;
}
69 changes: 28 additions & 41 deletions merge_sort_tree.cpp
Original file line number Diff line number Diff line change
@@ -1,83 +1,70 @@
struct merge_sort_tree
{
#define all(v) (v).begin(),(v).end()
struct merge_sort_tree{
vector<vector<int>> tree;
vector<int> a;
int n;
int base;
merge_sort_tree(int n): n(n)
{
merge_sort_tree(int n): n(n) {
base = 1;
while(base < n) base <<= 1;
tree.resize(base*2 - 1);
--base;
a.resize(n);
}
void init()
{
for (int i = base; i<base+n;++i)
{
void init() {
for (int i = base; i<base+n;++i) {
tree[i].resize(1);
tree[i][0] = a[i-base];
}
for (int i=base-1; i>=0; --i)
{
for (int i=base-1; i>=0; --i) {
tree[i].resize(tree[i*2+1].size() + tree[i*2+2].size());
merge(tree[i*2+1].begin(), tree[i*2+1].end(), tree[i*2+2].begin(), tree[i*2+2].end(), tree[i].begin());
merge(all(tree[2*i+1]), all(tree[2*i+2]), tree[i].begin());
}
}
int qry_ub(int qs, int qe, int val)//[qs, qe]에서 val이하 몇개?
{
//[qs, qe]에서 val이하 몇개?
int qry_ub(int qs, int qe, int val) {
int ret = 0;
qs += base;
qe += base+1;
for(; qs < qe; qs = qs / 2, qe = qe / 2)
{
if (qs%2 == 0)
{
ret += upper_bound(tree[qs].begin(), tree[qs].end(), val) - tree[qs].begin();
for(; qs < qe; qs = qs / 2, qe = qe / 2){
if (qs%2 == 0){
ret += upper_bound(all(tree[qs]), val) - tree[qs].begin();
++qs;
}
if (qe%2 == 0)
{
if (qe%2 == 0){
--qe;
ret += upper_bound(tree[qe].begin(), tree[qe].end(), val) - tree[qe].begin();
ret += upper_bound(all(tree[qe]), val) - tree[qe].begin();
}
}
return ret;
}
int qry_lb(int qs, int qe, int val)// [qs, qe]에서 val미만 몇개?
{
// [qs, qe]에서 val미만 몇개?
int qry_lb(int qs, int qe, int val){
int ret = 0;
qs += base;
qe += base+1;
for(; qs < qe; qs = qs / 2, qe = qe / 2)
{
if (qs%2 == 0)
{
ret += lower_bound(tree[qs].begin(), tree[qs].end(), val) - tree[qs].begin();
for(; qs < qe; qs = qs / 2, qe = qe / 2){
if (qs%2 == 0){
ret += lower_bound(all(tree[qs]), val) - tree[qs].begin();
++qs;
}
if (qe%2 == 0)
{
if (qe%2 == 0){
--qe;
ret += lower_bound(tree[qe].begin(), tree[qe].end(), val) - tree[qe].begin();
ret += lower_bound(all(tree[qe]), val) - tree[qe].begin();
}
}
return ret;
}
int qry_kth(int l, int r, int k)//배열 a에서, [l,r]에 속하는 '값'들만 고려 했을 때, k번째 원소의 index를 반환
{
//배열 a에서, [l,r]에 속하는 '값'들만 고려 했을 때, k번째 원소의 index를 반환
int qry_kth(int l, int r, int k){
int node = 0;
while(node < base)
{
int c = upper_bound(tree[node*2+1].begin(), tree[node*2+1].end(), r) -
lower_bound(tree[node*2+1].begin(), tree[node*2+1].end(), l);
if (c >= k)
{
while(node < base){
int c = upper_bound(all(tree[node*2+1]), r) -
lower_bound(all(tree[node*2+1]), l);
if (c >= k){
node = 2*node + 1;
}
else
{
else{
node = 2*node + 2;
k -= c;
}
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