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problem: new problem solution - 1347 . Minimum Number of Steps to Mak…
…e Two Strings Anagram
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...mNumberOfStepsToMakeTwoStringsAnagram/MinimumNumberOfStepsToMakeTwoStringsAnagram.test.ts
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// Source : https://leetcode.com/problems/minimum-number-of-steps-to-make-two-strings-anagram/ | ||
// Author : francisco | ||
// Date : 2024-01-13 | ||
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import { minSteps } from "./MinimumNumberOfStepsToMakeTwoStringsAnagram"; | ||
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describe("minimum number of steps to make two strings anagram", () => { | ||
test("example 1", () => { | ||
const result: number = minSteps("bab", "aba"); | ||
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expect(result).toBe(1); | ||
}); | ||
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test("example 2", () => { | ||
const result: number = minSteps("leetcode", "practice"); | ||
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expect(result).toBe(5); | ||
}); | ||
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test("example 3", () => { | ||
const result: number = minSteps("anagram", "mangaar"); | ||
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expect(result).toBe(0); | ||
}); | ||
}); |
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...inimumNumberOfStepsToMakeTwoStringsAnagram/MinimumNumberOfStepsToMakeTwoStringsAnagram.ts
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// Source : https://leetcode.com/problems/minimum-number-of-steps-to-make-two-strings-anagram/ | ||
// Author : francisco | ||
// Date : 2024-01-13 | ||
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/***************************************************************************************************** | ||
* | ||
* You are given two strings of the same length s and t. In one step you can choose any character of t | ||
* and replace it with another character. | ||
* | ||
* Return the minimum number of steps to make t an anagram of s. | ||
* | ||
* An Anagram of a string is a string that contains the same characters with a different (or the same) | ||
* ordering. | ||
* | ||
* Example 1: | ||
* | ||
* Input: s = "bab", t = "aba" | ||
* Output: 1 | ||
* Explanation: Replace the first 'a' in t with b, t = "bba" which is anagram of s. | ||
* | ||
* Example 2: | ||
* | ||
* Input: s = "leetcode", t = "practice" | ||
* Output: 5 | ||
* Explanation: Replace 'p', 'r', 'a', 'i' and 'c' from t with proper characters to make t anagram of | ||
* s. | ||
* | ||
* Example 3: | ||
* | ||
* Input: s = "anagram", t = "mangaar" | ||
* Output: 0 | ||
* Explanation: "anagram" and "mangaar" are anagrams. | ||
* | ||
* Constraints: | ||
* | ||
* 1 <= s.length <= 5 * 10^4 | ||
* s.length == t.length | ||
* s and t consist of lowercase English letters only. | ||
******************************************************************************************************/ | ||
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/** | ||
* @param {string} s | ||
* @param {string} t | ||
* @returns {number} | ||
* return the minimum number of steps to make t an anagram of s | ||
* Tests: | ||
* I: s = "bab", t = "aba" -> O: 1 | ||
* I: s = "leetcode", t = "practice" -> O: 5 | ||
* I: s = "anagram", t = "mangaar" -> O: 0 | ||
* Template: | ||
* iteration char of s, char - place the character and its count in a hastable | ||
* iteration char of t, char - if char in hashtable and count is greater than 0 sub 1 from it | ||
* else add 1 to total count acc | ||
* Time Complexity: O(n), where n is s.length === t.length | ||
* Space Complexity: O(1), since charCounts max length is 26(english alphabet length) | ||
*/ | ||
export function minSteps(s: string, t: string): number { | ||
const charCounts = new Map<string, number>(); | ||
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for (const char of s) charCounts.set(char, (charCounts.get(char) ?? 0) + 1); | ||
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let total: number = 0; | ||
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for (const char of t) { | ||
if ((charCounts.get(char) as number) > 0) | ||
charCounts.set(char, (charCounts.get(char) as number) - 1); | ||
else total++; | ||
} | ||
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return total; | ||
} |